maths past papers

Hi Friends!!!

How many of you scare to attend exams?

I have few tips and reasons which makes you tension free before attending exams.

Practicing maths past papers is the best way to gain perfection in subject and to complete your revision as you can test yourself under exam conditions, with the same three hour time constraint you'll have in the exam. I can say they are the most valuable resource for carrying out revision. Solving past papers enable students to gauge their subject knowledge and uncover their strengths and weaknesses, enabling you to understand what areas you need to devote more time to and conversely, what areas you can devote less time to.

It is the one of the most effective & easy way of increasing interest in learning and your chances of passing exams at school is to obtain past Test papers.There many websites which provides you free exam paper.
There are 4 reasons to solve maths past papers & English past papers:
1. It enables you to understand & establish the type of questions being asked.
2. How those questions will be marked. For exam some answers carry more points then others
3. You will learn how to manage your time during the exam.
4. It helps you to revise & review information from math books or math notes that are most important for the math exam.
One hand before you obtain past papers the better as it enables you to gear your revision around the typical type of questions that you are likely to get asked.
I hope the above explanation was useful.Keep reading and leave your comments.

grams to kilograms

Let us learn how to convert grams to kilograms.

Grams and kilograms both are the International System of Units, the standard units of measuring weight. Gram is a metric unit of mass which equals to one thousandth (1÷1000) of a kilogram.

Convert 1000 grams to kilograms.

Solution:

We know that one gram is equal to 0.001kilograms.

Therefore 1000 grams= 0.001x 1000 kilograms.

= 1 kilograms.

In our next blog we shall learn about logarithm rules I hope the above explanation was useful.Keep reading and leave your comments.

Introduction to Analytic Geometry

Let us learn about Analytic Geometry.

Introduction to Analytic Geometry:

In plane analytic geometry, points are defined as ordered pairs of numbers, say, (x, y), while the straight lines are in turn defined as the sets of points that satisfy linear equations.

Analytic Geometry is a branch of algebra that is used to model geometric objects - points, (straight) lines, and circles being the most basic of these. Analytic geometry is a great invention of Descartes and Fermat. Analytical geometry is also known as coordinate geometry or Analytical Cartesian coordinate system.

The study of analytical geometry related to coordinate system and the principles of algebra and analysis. The synthetic approach of Euclidean geometry is the contrast geometry, which treats certain geometric notions as primitive, and uses deductive reasoning based on axioms and theorems to derive truth.

I hope the above explanation was useful.Keep reading and leave your comments.

algebra 1 helper

Hi Friends!!!


What do you think whether books like algebra 1 helper, help on homework , free math answers so on will help you in solving problems or online tutors helps you in learning math better.

Online means it is one of the new way of connectivity it is victimized for introduce the two or author soul in a equal period from that they do the conversation finished the computer, web equivalent that. Here the grad can greet meliorate from the tutor.

online homework help from online tutors proved better learning processes from media of learning. Many students scored good marks in their semesters.

I hope the above explanation was useful.Keep reading and leave your comments.

how to solve math problems

Hi Friends!!!

Math isn’t that hard! In fact it’s probably one of the simpler sciences. That said it could be confusing in case you don’t know what to do. Definitely there's overwhelming issues in math (and even types of math where getting the wrong answer is the whole point!) but most math can be broken down in to simple solvable steps.

now let us learn how to solve math problems

Have you heard any time practice makes man perfect.

Math is an interesting subject. We need to practice daily and we should learn even a simple basic method to solve difficult problems.

There are many websites which provides you free math answers.
If you need more help on homework, online tutoring is best example to make you tension free.
In our next blog we shall learn about Pre algebra I hope the above explanation was useful.Keep reading and leave your comments.

what does mean in math

what does mean in math ?


In mathematics, an average, central tendency of a data set is a measure of the "middle" or "expected" value of the data set. The average is calculated by combining the values from the set in a specific way and computing a single number as being the average of the set. The most common method is the arithmetic mean

Average or mean =. Sum of all numbers

The count of the number

In our next blog we shall learn about parts of an atom I hope the above explanation was useful.Keep reading and leave your comments.

division algorithm

Let us learn about division algorithm

In mathematics, polynomials in more than one variable do not form a Euclidean domain, so it is not possible to construct a true division algorithm. Given a polynomial g, polynomials (f₁, ..., f_m) and an order on the monomials in k[x₁, ..., x_n], we construct the reduction of g modulo f₁, ..., f_m by the following algorithm. Let a_i denote the leading term of f_i with respect to the monomial order. Repeatedly apply the following until no monomial term of g is divisible by any of the a_i :

Division Algorithm for Polynomials

Let F is a field, f(x), g(x) e F[x] with g(x) ≠ 0.

In q(x), r(x) in the F[x] such that f(x) = g(x) q(x) + r(x) and r(x) =0

Proof :-
(1) Let f(x) = g(x) q(x) + r(x) with g(x) ≠ 0

(2) If f(x) = 0 or deg f(x) is less than g(x), then r(x)=f(x), q(x)=0.

(3) So, we assume that f(x) ≠ 0 and deg f(x) ≥ deg g(x)

(4) Let f(x) = a_nxⁿ + ... + a₀

(5) Let g(x) = b_mx^m + ... + b₀

(6) Let f₁(x) = f(x) - a_nb_m^-1x^n-mg(x)

(7) We note that deg f₁(x) is <>deg f(x) since:

f(x) - a_nb_m^-1x^n-mg(x)

= a_nxⁿ + ... + a₀ - a_nb_m^-1x^n-m(b_mx^m + ... + b₀)

= a_nⁿ - a_nxⁿ + a_n-1x^n-1 + ... + a₀ - a_nb_m^-1b_m-1x^n-1 - ... - a_nb_m^-1b₀x^n-m

= a_n-1x^n-1 + ... + a₀ - a_nb_m^-1b_m-1x^n-1 - ... - a_nb_m^-1b₀x^n-m

So that f₁(x) has a degree of n-1 while f(x) has a degree of n.

In our next blog we shall learn about cleavage furrow I hope the above explanation was useful.Keep reading and leave your